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21. (a/1)+(a²/2)+(a³/3)+(a⁴/4)+... :—
#include<stdio.h>
int main()
{
int i,n,a,sum;
printf("enter value of n and a ");
scanf("%d%d",&n,&a);
sum=0;
for(i=1;i<=n;i++)
sum=sum+pow(a,i)/(float)i;
}
printf("%d",sum);
return 0;
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