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Wednesday, May 27, 2020
Monday, May 25, 2020
java theory question set 4
BALAGURUSAMY CHAPTER 4::
| SL. NO | QUESTION | MARKS | PAGE NO | LINK1 | LINK2 | LINK3 |
| 1. | PRIMITIVE ,NON PRIMITIVE DATA TYPES | 2 | 46 | |||
| 2. | SIZE AND RANGE OF DATA TYPES | 2 | 48 | |||
| 3. | SCOPE OF VARIABLES | 2 | 51 | |||
| 4. | TYPE CASTING | 2 | 53 | |||
| 5. | AUTO TYPE CASTING | 2 | 53 | |||
| 6. | DEFAULT VALUE OF DATA TYPE | 2 | 57 |
java theory question set 3
BALAGURUSAMY CHAPTER 3::
| SL. NO | QUESTION | MARKS | PAGE NO | LINK1 | LINK2 | LINK3 |
| 1. | WHY MAIN() IS STATIC | 2 | 26 | |||
| 2. | TOKEN | 2 | 30 | |||
| 3. | LITERALS | 33 | ||||
| 4. | SEPARATORS | 34 | ||||
| 5. | CLASSIFICATION OF JAVA STATEMENTS | 36 | ||||
| 6. | JAVA VIRTUAL MACHINE | 39 | ||||
| 7. | COMMAND LINE ARGUMENT | 40 |
java theory question set 2
BALAGURUSAMY CHAPTER 2::
| SL. NO | QUESTION | MARKS | PAGE NO | LINK1 | LINK2 | LINK3 |
| 1. | COMPILER AND INTERPRETER | 4 | 13 | |||
| 2. | BYTECODE | 2 | 13 | |||
| 3. | JVM | |||||
| 4. | COMPARE WITH C AND C++ | 3 | 15 | |||
| 5. | JAVA DEVELOPMENT TOOLS | TABLE 2.3 | ||||
| 6. | APPLICATION PROGRAMMING INTERFACE | 22 |
java theory question set 1
BALAGURUSWAMY CHAPTER 1::
| SL. NO | QUESTION | MARKS | PAGE NO | LINK1 | LINK2 | LINK3 |
| 1. | DATA ABSTRACTION | 2 | 4 | |||
| 2. | ENCAPSULATION | 2 | 4 | |||
| 3. | INHERITANCE | 2 | 4 | |||
| 4. | POLYMORPHISM | 2 | 5 | |||
| 5. | DYNAMIC BINDING | 2 | 6 | |||
| 6. | MESSAGE COMMUNICATION | 2 | 6 | |||
| 7. | BENEFIT OF OOPS | 3 | 8 |
Tuesday, May 19, 2020
COMPUTER ARCHITECTURE LAB ASSIGNMENT
| 1. | LDA , STA instruction IN COMPUTER ARCHITECTURE | LINK |
| 2. | addition of two hexadecimal numbers | LINK |
| 3. | addition of three hexadecimal numbers | LINK |
| 4. | 1'S COMPLEMENT OF A NUMBER | LINK |
| 5. | 2'S COMPLEMENT OF A NUMBER | LINK |
| 6. | SUBTRACTION of two hexadecimal number | LINK |
| 7. | LDA DIRECT MODE , INDIRECT MODE | LINK |
| 8. | STA direct mode indirect mode | LINK |
| 9. | ADD DIRECT MODE INDIRECT MODE | LINK |
| 10. | AND INSTRUCTION DIRECT INDIRECT MODE | LINK |
| 11. | OR OPERATION USING AND INSTRUCTION | LINK |
| 12. | ADDITION OF TWO DECIMAL ADDITION | LINK |
| 13. | CIR INSTRUCTION | LINK |
| 14. | CIL INSTRUCTION | LINK |
| 15. | CLE,CME INSTRUCTION | LINK |
| 16. | 4TIMES CIL | LINK |
| 17. | 4TIMES CIR | LINK |
| 18. | BUN INSTRUCTION | LINK |
| 19. | ISZ INSTRUCTION | LINK |
| 20. | SPA INSTRUCTION | LINK |
| 21. | SNA INSTRUCTION | LINK |
| 22. | SZA INSTRUCTION | LINK |
| 23. | SZE INSTRUCTION | LINK |
sta direct mode indirect mode BY BIJAN KRISHNA PAUL
sta direct mode indirect mode BY BIJAN KRISHNA PAUL
AND INSTRUCTION DIRECT INDIRECT MODE BY BIJAN KRISHNA PAUL
AND INSTRUCTION DIRECT INDIRECT MODE BY BIJAN KRISHNA PAUL
ADD DIRECT MODE INDIRECT MODE BY BIJAN KRISHNA PAUL
ADD DIRECT MODE INDIRECT MODE BY BIJAN KRISHNA PAUL
LDA DIRECT MODE INDIRECT MODE BY BIJAN KRISHNA PAUL
LDA DIRECT MODE INDIRECT MODE BY BIJAN KRISHNA PAUL
postfix++,prefix++ unary operator in c language example
postfix++,prefix++ unary operator in c language example
Friday, May 15, 2020
West Bengal Board class 11 visual basic program 4. get input from inputbox and check it is positive negative or zero
West Bengal Board class 11 visual basic program 4. get input from inputbox and check it is positive negative or zero
End Sub
Get input using inputbox, and then check it is positive or negative or zero in vb6,print using msgbox (visual basic)
Private Sub Form_Load()
Dim a As Integer
a = Int(InputBox("enter a number"))
If a = 0 Then
MsgBox (a & "is zero")
ElseIf a > 0 Then
MsgBox (a & "is positive")
Else
MsgBox (a & "is nagetive")
End If
West Bengal Board class 11 visual basic program 3. get input using inputbox and then sum of digit
West Bengal Board class 11 visual basic program 3. get input using inputbox and then sum of digit
Get input using inputbox, and then sum of digits (2digit) and display using msgbox in vb6(visual basic)
Private Sub Form_Load()
Dim a, b, c As Integer
a = Int(InputBox("enter a number"))
b = a Mod 10
c = a \ 10
d = b + c
MsgBox (d)
End Sub
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