Thursday, February 28, 2019

UNIX COMMAND

1. Find the current time and date.

[bgc@localhost ~]$ date
Thu Aug 23 04:54:01 EDT 2018
[bgc@localhost ~]$

2. Create a blank file.

[bgc@localhost ~]$ touch aniket.txt
[bgc@localhost ~]$

3. Create a file and write some sentences on the file.

[bgc@localhost ~]$ cat>file1.txt
today is thursday
I am a student
Bhairab Ganguly College
[bgc@localhost ~]$

4. Display the content of the file file1.txt

[bgc@localhost ~]$ cat file1.txt
today is thursday
I am a student
Bhairab Ganguly College
[bgc@localhost ~]$

5. Append some lines in a text file.

[bgc@localhost ~]$ cat>>file1.txt
tomorrow is friday
[bgc@localhost ~]$ cat file1.txt
today is thursday
I am a student
Bhairab Ganguly College
tomorrow is friday
[bgc@localhost ~]$

6. Create a directory or folder.

[bgc@localhost ~]$ mkdir Aniket
[bgc@localhost ~]$

7. Display all files and directories under the current directory.

[bgc@localhost ~]$ dir
10.sh~      7.sh~      even   nelash.sh
143.cpp~      8a.sh      evenoddchecking.sh   nelash.sh~
144.cpp~      8a.sh~      evenoddchecking.sh~  nelash.txt
145.cpp~      8.sh      f1   nelash.txt~
146.cpp~      8.sh~      f2.cpp~   odd
147.cpp~      9.sh~      f8.cpp~   p1.cpp~
148.cpp.cpp~  a      file1.txt   p2.cpp~
149.cpp~      A\ K\ PATWA\ 9564\ BGC  file.c~   p3.cpp~
150.cpp~      aman~      file.txt   paddy
151.cpp~      aman2~      file.txt~   paddy1.txt
152.cpp~      Aniket      final.c   Pictures
153.cpp~      aniket.txt      first.c~   Public
154.cpp~      aniket.txt~      F_to_c.cpp~   puli1.c~
1.sh      archie.sh      HMS.cpp~   rajdeep.doc
1.sh~      archie.sh~      joy   rajdeep.txt
2.sh      Archisman.sh      joy1.sh   rajdeep.txt~
2.sh~      Archisman.sh~      joyblank.sh   reverse.sh
3.sh      Archisman.txt      joyblank.sh~   reverse.sh~
3.sh~      Archisman.txt~      joymarks.sh   sdsir.c~
4.sh      arm.sh      joyword.sh   source.txt
4.sh~      arm.sh~      joyword.sh~   student1.txt
5.sh      assignment1.sh      joyyy.sh   student1.txt~
5.sh~      assignment1.sh~      joyyy.sh~   t19.txt
6a.sh~      bubble.c~      km_to_mile.cpp~   t2.txt
6b.sh~      checking.sh      linear.sh   t2.txt~
6c.sh~      Debayan      linear.sh~   Templates
6.sh      Desktop      Music   triangle.txt~
6.sh~      destination.txt      nealash2.txt   Untitled\ Folder
7a.sh~      Documents      nelash2.sh   Videos
7b.sh~      Downloads      nelash2.sh~   vowelcheck.txt
7c.sh~      DtoB.sh      nelash3.sh
7.sh      DtoB.sh~      nelash3.sh~
[bgc@localhost ~]$

8. Display all files and directories under the current directory.

[bgc@localhost ~]$ ls
10.sh~        7.sh~      even nelash.sh
143.cpp~      8a.sh      evenoddchecking.sh nelash.sh~
144.cpp~      8a.sh~      evenoddchecking.sh~ nelash.txt
145.cpp~      8.sh      f1 nelash.txt~
146.cpp~      8.sh~      f2.cpp~ odd
147.cpp~      9.sh~      f8.cpp~ p1.cpp~
148.cpp.cpp~  a      file1.txt p2.cpp~
149.cpp~      A K PATWA 9564 BGC  file.c~ p3.cpp~
150.cpp~      aman~      file.txt paddy
151.cpp~      aman2~      file.txt~ paddy1.txt
152.cpp~      Aniket      final.c Pictures
153.cpp~      aniket.txt      first.c~ Public
154.cpp~      aniket.txt~      F_to_c.cpp~ puli1.c~
1.sh          archie.sh      HMS.cpp~ rajdeep.doc
1.sh~         archie.sh~      joy rajdeep.txt
2.sh          Archisman.sh      joy1.sh rajdeep.txt~
2.sh~         Archisman.sh~      joyblank.sh reverse.sh
3.sh          Archisman.txt      joyblank.sh~ reverse.sh~
3.sh~         Archisman.txt~      joymarks.sh sdsir.c~
4.sh          arm.sh      joyword.sh source.txt
4.sh~         arm.sh~      joyword.sh~ student1.txt
5.sh          assignment1.sh      joyyy.sh student1.txt~
5.sh~         assignment1.sh~     joyyy.sh~ t19.txt
6a.sh~        bubble.c~      km_to_mile.cpp~ t2.txt
6b.sh~        checking.sh      linear.sh t2.txt~
6c.sh~        Debayan      linear.sh~ Templates
6.sh          Desktop      Music triangle.txt~
6.sh~         destination.txt     nealash2.txt Untitled Folder
7a.sh~        Documents      nelash2.sh Videos
7b.sh~        Downloads      nelash2.sh~ vowelcheck.txt
7c.sh~        DtoB.sh      nelash3.sh
7.sh          DtoB.sh~      nelash3.sh~
[bgc@localhost ~]$

9. Details of all processes that are currently executing

[bgc@localhost ~]$ ps
 PID   TTY       TIME CMD
2807 pts/1    00:00:00 bash
2889 pts/1    00:00:00 ps

[bgc@localhost ~]$

BASIC DOS COMMAND

1.create a sub directory NEW and a sub directory EXAM under it.
C:\Users\cs-14>md NEW

C:\Users\cs-14>cd NEW

C:\Users\cs-14\NEW>md EXAM

C:\Users\cs-14\NEW>cd EXAM
2. create two files TEST1 and TEST2 in a sub directory EXAM.
C:\Users\cs-14\NEW\EXAM>copy con TEST1
CMSA^Z
       1 file(s) copied.

C:\Users\cs-14\NEW\EXAM>copy con TEST2
MTMG^Z
       1 file(s) copied.
3.copy the contain of TEST1 into TEST3.
C:\Users\cs-14\NEW\EXAM>copy TEST1 TEST3
       1 file(s) copied.
4. Delete the file TEST1.
C:\Users\cs-14\NEW\EXAM>del TEST1
5.Rename the file TEST3 toTEST4.
C:\Users\cs-14\NEW\EXAM>ren TEST3 TEST4
6.Display the file TEST1.
C:\Users\cs-14\NEW\EXAM>edit TEST1
7.delete the folder EXAM.
C:\Users\cs-14\NEW\EXAM>del TEST2

C:\Users\cs-14\NEW\EXAM>del TEST4
    
C:\Users\cs-14\NEW\EXAM>cd..

C:\Users\cs-14\NEW>rd EXAM
8.Delete the folder NEW.
C:\Users\cs-14\NEW>cd..

C:\Users\cs-14>rd NEW

C:\Users\cs-14>

LCM OF TWO NUMBERS


#include<stdio.h>
void main()
{
 int a,b,i,l;
 printf("enter the first element");
 scanf("%d",&a);
 printf("enter the second element");
 scanf("%d",&b);
 for(i=1;;i++)
 {
  if(i%a==0&&i%b==0)
  {
   l=i;
   break;
  }
 }
 printf("%d",l);
}

GCD OF TWO NUMBERS C LANGUAGE CODE


Program code:
#include<stdio.h>
void main()
{
 int m,n,i,g;
 printf("enter the first element");
 scanf("%d",&m);
 printf("enter the second element");
 scanf("%d",&n);
 for(i=1;i<=m;i++)
 {
  if(m%i==0&&n%i==0)
  {
   g=i;
  }
 }
 printf("%d",g);
}

PASCAL'S TRIANGLE CODE USING C LANGUAGE


#include<stdio.h>
void main()
{
 int n,i,j,a[30][30];
 printf("enter the number of line");
 scanf("%d",&n);
 for(i=0;i<=n;i++)
 {
  for(j=0;j<=i;j++)
  {
   if(j==0||i==j)
   {
    a[i][j]=1;
   }
   else
   {
    a[i][j]=a[i-1][j]+a[i-1][j-1];
   }
  }
 }
 for(i=0;i<n;i++)
 {
  for(j=0;j<(n-i-1);j++)
  {
   printf(" ");
  }
  for(j=0;j<=i;j++)
  {
   printf("%d",a[i][j]);
  }
  printf("\n");
 }
}

FLOY'D TRINAGLE CODE IN C LANGUAGE





#include<stdio.h>
void main()
{
                int i,j,k,l,n;
                printf("enter the total number of line");
                scanf("%d",&n);
                l=1;
                for(i=1;i<=n;i++)
                {
                                for(j=1;j<=(n-i);j++)
                                {
                                                printf(" ");
                                }
                                for(k=1;k<=i;k++)
                                {
                                                printf("%d ",l++);
                                }
                                printf("\n");
                }
}

Tuesday, February 19, 2019

Get input using inputbox, and then check it is positive or negative or zero in vb6,print using msgbox (visual basic)


Private Sub Form_Load()
Dim a As Integer
a = Int(InputBox("enter a number"))
If a = 0 Then
MsgBox (a & "is zero")
ElseIf a > 0 Then
MsgBox (a & "is positive")
Else
MsgBox (a & "is nagetive")
End If
 End Sub

Get input using inputbox, and then sum of digits (2digit) and display using msgbox in vb6(visual basic)


Private Sub Form_Load()
Dim a, b, c As Integer
a = Int(InputBox("enter a number"))
b = a Mod 10
c = a \ 10
d = b + c
MsgBox (d)
End Sub

Get input using inputbox, and then sum of two numbers and print using msgbox in vb6(visual basic)

Private Sub Form_Load()
Dim a, b, c As Integer
a = Int(InputBox("enter a number"))
b = Int(InputBox("enter a number"))
c = a + b
MsgBox (c)
End Sub

Friday, February 15, 2019

wbsu 2016 dbms practical question


                                                                                                                                 edited by- joy

create table boat(bid varchar2(10) primary key,bname varchar2(10),color varchar2(10));
create table sailor(sid varchar2(10) primary key,sname varchar2(10),rating number);
create table reserve(sid varchar2(10) references sailor, bid varchar2(10) references boat, day varchar2(10));
insert into boats values('001','titanic','red');
insert into boats values('002','gulliver','green');
insert into boats values('003','crusoe','red');
insert into boats values('004','shanok','green');
insert into boats values('005','paradise','yellow');
insert into sailors values('A01','varshan','6');
insert into sailors values('A02','ashutosh','7');
insert into sailors values('A03','anindo','5');
insert into sailors values('A04','akash','9');
insert into sailors values('A05','ashutosh','8');
insert into reserves values('A01','001','sunday');
insert into reserves values('A01','003','wednesday');
insert into reserves values('A01','002','monday');
insert into reserves values('A01','004','thurshday');
insert into reserves values('A02','001','monday');
insert into reserves values('A03','001','tueday');
insert into reserves values('A03','003','friday');
insert into reserves values('A04','004','saturday');
insert into reserves values('A04','001','wednesday');
insert into reserves values('A05','001','sunday');       




select * from boats
B_ID
B_NAME
COLOR
001
titanic
red
002
gulliver
green
003
crusoe
red
004
shanok
green
005
paradise
yellow

select * from sailors
SID
SNAME
RATING
A01
varshan
6
A02
ashutosh
7
A03
anindo
5
A04
akash
9
A05
ashutosh
8



select * from reserves
SID
BID
DAY
A01
001
sunday
A01
003
wednesday
A01
002
monday
A01
004
thurshday
A02
001
monday
A03
001
tuesday
A03
003
friday
A04
004
saturday
A04
001
wednesday
A05
001
monday








1.find the name of sailors who have reserved red boats but not green boats?
select sname from sailors,boats,reserves where sailors.sid=reserves.sid and
 boats.bid=reserves.bid and
color='red'
minus
select sname
from sailors,boats,reserves
where sailors.sid=reserves.sid and
 boats.bid=reserves.bid and
color='green';
SNAME
anindo
ashutosh


2.find  the name of boats which are reserved by all sailors?
(division using minus and not exists)

select bname from   boats  where not exists           
                     ((select sid  from sailors )minus(select sid from reserves where  boats.bid=reserves.bid));
BNAME
titanic